Naturally occurring boron is 80.20% boron 11(atomic mass 11.01 daltons) and 19.80% of some other isotope. What must the mass of the other isotope be in order to have an average atomic mass of 10.81 daltons?
80.29% multiplied by 11.01 will give you 8.83 19.80% multiplied by X will end up as .198X Add your two results together, 8.83 + .198X, and you will end up with 9.028.
80.20% of 11.01 daltons = 8.830 daltons (.8020 multiplied by 11.01) 19.80% of x daltons = .1980x (.1980 multiplied by x) 8.830 + .1980x = 10.81 (subtract 8.830 from both sides) .1980x = 1.980 (divide .1980 on both sides) x = 10.00 daltons
80.20% of 11.01 daltonss = 8.830 daltons ( multiply .8020 by 11.01) 19.80% of x daltons = .1980x ( multiply .1980 by x) 8.830 + .1980x = 10.81 (subtract 8.830 from both sides) .1980x = 1.980 (divide .1980 to both sides)
then you will get an answer of.. x = 10.00 daltons
80.20% x 11.01amu = 8.83
ReplyDelete19.80% x X mass = .1980X
8.83 + .1980X = 10.81
.1980X = 1.98
X Mass = 10 daltons
* = multiply
ReplyDelete80.20% = .8020
19.80% = .1980
.8020 * 11.01 = 8.830
.1980 * x = .1980x
8.830 + .1980x = 10.81
.1980x = 10.81 - 8.830
.1980x = 1.98
x = 1.98 / .1980
x = mass = 10
10 daltons*
ReplyDelete80.20% x 11.01 = 8.83
ReplyDelete19.80% x Xmass = .198X
8.83 + .198x = 9.028
.198x = 1.98
X mass = 10 daltons
Baron 11
ReplyDelete80.20% ; 11.01amu
multiply these = 8.83
?Baron
X equals mass
19.80% x X = 1980X
10.81amu= 1980X + 8.83
subtract 8.83 from both sides
1.98= 1980X
divide
0.1= X
move decimal 2 places to the right
=10amu
80.20% x 11.01 = 8.83
ReplyDelete19.80% x X = .1980X
8.83 + .1980X = 10.81
.1980X = 1.98
Mass = 10
Andy, don't forget your units!!!!
ReplyDelete80.20% x 11.01 = 8.83
ReplyDelete19.80% x Xmass = .198X
8.83 + .198x = 9.028
.198x = 1.98
X mass = 10 daltons
This comment has been removed by the author.
ReplyDelete80.20% x 11.01= 8.83
ReplyDelete19.80 x X= 19.80X
19.80X + 8.83= 10.81amu
subtract 8.83 from both sides
1.93=.198X
X=10 daltons
80.29% multiplied by 11.01 will give you 8.83
ReplyDelete19.80% multiplied by X will end up as .198X
Add your two results together, 8.83 + .198X, and you will end up with 9.028.
.198X = 1.98
X must equal 10 daltons.
80.20% x 11.01= 8.83
ReplyDelete19.80 x (X)= 19.80X
19.80X + 8.83= 10.81 amu
1.93= .198X
X= 10 daltons
80.20% x 11.01 = 8.83
ReplyDelete19.80% x (n) mass = .1980X
8.83 + .1980(n) = 10.81
.1980X = 1.98
(N) Mass = 10 dal
80.20% x 11.01amu= 8.83
ReplyDelete19.80 x mass(X)= 19.80X
19.80X + 8.83= 10.81 amu
1.93= .198X
X= 10 daltons
n= atomic mass of second isotope
ReplyDelete80.20%x11.01=8.83
19.80%x n=.1980n
8.83+.1980n=10.81 daltons
.1980n=1.98
n=10 daltons
80.20% x 11.01amu =8.83
ReplyDelete19.80x X mass= 19.80X
19.80X + 8.83= 10.81amu
1.93=.198X
X mass= 10 daltons
-Anna Petrossian
80.20% * 11.01 = 8.83
ReplyDelete19.80% * x = .198x
8.83 + .198x = 9.028
.198x = 1.98
x = 10 daltons
Natalie Bedrosian
ReplyDelete80.20% *11.01=8.83
19.80%*x=.1980x
8.83+.198x=10.81
.1980x=1.98
x=10 daltons
80.20 * 11.01 = 8.83
ReplyDelete19.80 * x = 19.80X
19.80x + 8.83 = 10.81 amu
1.93 = 0.198x
x = 10 daltons
80.20% *11.01=8.83
ReplyDelete19.80%*x=.1980x
8.83+.198x=10.81
.1980x=1.98
x=10 daltons
80.20(11.01)= 8.83
ReplyDelete19.80(X)= .1980x
8.83 + .1980X = 10.81
.1980X = 1.98
mass= 10 daltons
80.20 x 11.01amu = 8.83
ReplyDelete19.80 x X mass = .1980X
8.83 + .1980X = 10.81
.1980X = 1.98
(x)mass =10 daltons
(80.20%)(11.01) = 8.83
ReplyDelete(19.80%)x = 0.198x
8.83 + 0.198x = 10.81
0.198x = 1.98
x = 10 Daltons
80.20% x 11.01 = 8.83
ReplyDelete19.80% x (n) mass = .1980X
8.83 + .1980(n) = 10.81
.1980X = 1.98
(N) Mass = 10 dal
SEVANA NOURIAN
ReplyDelete80.20% x 11.01amu = 8.83
19.80% x mass(x) = .1980X
8.83 + .1980X = 10.81
.1980X = 1.98
X Mass = 10 daltons
80.20% of 11.01 daltons = 8.830 daltons (.8020 multiplied by 11.01)
ReplyDelete19.80% of x daltons = .1980x (.1980 multiplied by x)
8.830 + .1980x = 10.81
(subtract 8.830 from both sides)
.1980x = 1.980
(divide .1980 on both sides)
x = 10.00 daltons
80.20% of 11.01 daltonss = 8.830 daltons ( multiply .8020 by 11.01)
ReplyDelete19.80% of x daltons = .1980x ( multiply .1980 by x)
8.830 + .1980x = 10.81
(subtract 8.830 from both sides)
.1980x = 1.980
(divide .1980 to both sides)
then you will get an answer of..
x = 10.00 daltons
11.01(.8020%) = 8.830 daltons
ReplyDeletex(.1980%) = .1908x
8.830 = .1980x = 10.81
1980x = 1.980
x=10.00 daltons