Thursday, September 15, 2011

Blog 5 Chemistry

IDENTIFY THE FOLLOWING ELEMENTS BASED ON THE ELECTRON CONFIGURATION:

A. 1S22S2SP5=
B. 1S22S22P63S1
C. 1S22S22P63S23P4
D. [Ne] 3S23P1
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29 comments:

  1. Ani KechichianSeptember 15, 2011 at 5:46 PM

    Okayy soooooo.....
    A is Fluorine (F)
    B is Sodium (Na)
    C is Sulfur (S)
    D is Aluminum (Al)

    ReplyDelete
  2. Natalie.KSeptember 16, 2011 at 4:39 PM

    A: Fluorine
    B: Sodium
    C: Sulfur
    D: Aluminum

    ReplyDelete
  3. Farah KandahSeptember 16, 2011 at 5:08 PM

    A: 1s22s2sp5 = Flourine
    B: 1s22s22p63s1 = Sodium
    C: 1s22s22p63s23p4 = Sulfur
    D: [Ne] 3s23p1 = Aluminum

    ReplyDelete
  4. lara kSeptember 16, 2011 at 5:18 PM

    A. 1S22S2P5=flourine
    B. 1S22S22P63S1= sodium
    C. 1S22S22P63S23P4= sulfur
    D. [Ne] 3S23P1= aluminum

    ReplyDelete
  5. Levon G.September 17, 2011 at 10:07 AM

    A: Fluorine
    B: Sodium
    C: Sulfur
    D: Aluminum

    ReplyDelete
  6. AnonymousSeptember 17, 2011 at 9:09 PM

    A. 1S22S2SP5= Fluorine
    B. 1S22S22P63S1= Sodium
    C. 1S22S22P63S23P4= Sulfur
    D. [Ne] 3S23P1= Aluminum

    ReplyDelete
  7. pauline baktiSeptember 17, 2011 at 10:02 PM

    A. 1S22S2P5=flourine
    B. 1S22S22P63S1= sodium
    C. 1S22S22P63S23P4= sulfur
    D. [Ne] 3S23P1= aluminum

    ReplyDelete
  8. shantpoladianSeptember 18, 2011 at 12:26 AM

    A. 1S22S2SP5=fluorine
    B. 1S22S22P63S1=sodium
    C. 1S22S22P63S23P4=sulfur
    D. [Ne] 3S23P1=aluminum

    ReplyDelete
  9. AnonymousSeptember 18, 2011 at 9:34 AM

    A = Fluorine
    B = Sodium
    C = Sulfur
    D = Aluminum

    ReplyDelete
  10. AnonymousSeptember 18, 2011 at 11:28 AM

    A= Fluorine
    B=Sodium
    C= Sulfur
    D= Aluminum

    -Anna Petrossian

    ReplyDelete
  11. AnonymousSeptember 18, 2011 at 11:35 AM

    A. 1S22S2SP5= Flourine
    B. 1S22S22P63S1= Sodium
    C. 1S22S22P63S23P4= Sulfur
    D. [Ne] 3S23P1= Aluminum

    Natalie Bedrosian

    ReplyDelete
  12. AnonymousSeptember 18, 2011 at 11:39 AM

    A: 1s22s2sp5 = Flourine
    B: 1s22s22p63s1 = Sodium
    C: 1s22s22p63s23p4 = Sulfur
    D: [Ne] 3s23p1 = Aluminum

    ReplyDelete
  13. AnonymousSeptember 18, 2011 at 1:27 PM

    A. 1S22S2SP5= Florine
    B. 1S22S22P63S1= Sodium
    C. 1S22S22P63S23P4= Sulfur
    D. [Ne]3S23P1= Aluminum

    ReplyDelete
  14. Andy DanayanSeptember 18, 2011 at 1:44 PM

    A. 1S22S2SP5= Fluorine
    B. 1S22S22P63S1= Sodium
    C. 1S22S22P63S23P4= Sulfur
    D. [Ne] 3S23P1= Aluminum

    ReplyDelete
  15. Mr. PSeptember 18, 2011 at 1:48 PM

    Impressive! I am looking forward to having some of you demonstrate how you solved this tomorrow in class!

    ReplyDelete
  16. AregSeptember 18, 2011 at 5:21 PM

    A. fluorine
    B. Sodium
    C. Sulfur
    D. Aluminum

    ReplyDelete
  17. ArteenSeptember 18, 2011 at 7:32 PM

    A. Fluorine (F)
    B. Sodium (Na)
    C. Sulfur (S)
    D. Aluminum (Al)

    ReplyDelete
  18. ChristinaMarkarSeptember 18, 2011 at 7:34 PM

    A) Fluorine(F)
    B) Sodium (Na)
    C) Sulfur (S)
    D) Aluminum (Al)
    Christina Markarian

    ReplyDelete
  19. UnknownSeptember 18, 2011 at 7:55 PM

    This comment has been removed by the author.

    ReplyDelete
  20. UnknownSeptember 18, 2011 at 7:56 PM

    A. 1S22S2SP5= Fluorine (F)
    B. 1S22S22P63S1= Sodium (Na)
    C. 1S22S22P63S23P4= Sulfur (S)
    D. [Ne] 3S23P1= Aluminum (Al)
    Vatche Antekelian

    ReplyDelete
  21. suroSeptember 18, 2011 at 9:00 PM

    A. 1S22S2SP5= Fluorine (F)
    B. 1S22S22P63S1= Sodium (Na)
    C. 1S22S22P63S23P4= Sulfur (S)
    D. [Ne] 3S23P1= Aluminum (Al)

    i double checked it on http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch6/quantum.html

    ReplyDelete
  22. AnonymousSeptember 18, 2011 at 9:44 PM

    A is Flourine
    B is Sodium
    C is Sulfur
    D is Aluminum

    ReplyDelete
  23. ShawntSeptember 18, 2011 at 10:12 PM

    A-1S22S2SP5= Fluorine (F)
    B-1S22S22P63S1= Sodium (Na)
    C-1S22S22P63S23P4= Sulfur (S)
    D-[Ne]3S23P1= Aluminum (Al)

    ReplyDelete
  24. Lynna OhanianSeptember 18, 2011 at 11:54 PM

    A. 1S22S2SP5= Fluorine
    B. 1S22S22P63S1= Sodium
    C. 1S22S22P63S23P4= Sulfur
    D. [Ne] 3S23P1= Aluminum

    http://www.wikihow.com/Write-Electron-Configurations-for-Atoms-of-Any-Element

    ReplyDelete
  25. garySeptember 18, 2011 at 11:58 PM

    A.1S22S2SP5=fluorine (F)
    B.1S22S22P63S1=sodium (Na)
    C.1S22S22P63S23P4=sulfur (S)
    D.(Ne)3S23P1=aluminum (Al)

    ReplyDelete
  26. AnonymousSeptember 19, 2011 at 12:20 AM

    a. 1S22S2SP5 - Fluorine (F)
    b. 1S22S22P63S1 - Sodium (Na)
    c. 1S22S22P63S23P4 - Sulfur (S)
    d. [Ne] 3S23P1 - Aluminum (Al)

    ReplyDelete
  27. Garo KSeptember 19, 2011 at 11:08 AM

    A. 1S22S2P5=flourine
    B. 1S22S22P63S1= sodium
    C. 1S22S22P63S23P4= sulfur
    D. [Ne] 3S23P1= aluminum

    ReplyDelete
  28. AnonymousSeptember 22, 2011 at 6:04 PM

    A: Fluorine
    B: Sodium
    C: Sulfur
    D: Aluminum

    arthur s

    ReplyDelete
  29. AnonymousOctober 2, 2011 at 8:38 PM

    Na+ : 1s2 2s2 2p6
    Rb+ = [Ar] 3d10 4s2 4p6
    O2- = 1s2 2s2 2p6
    Br- = [Ar] 3d10 4s2 4p6
    Ca+ = [Ar] 4s1
    Al3+ = 1s2 2s2 2p6
    S2- = [Ne] 3s2 3p6

    Na+, O2-, and Al3+ do not have noble gas configurations.
    -Anna Petrossian

    ReplyDelete

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