What is the wavelength of a wave with an energy of 1,000,000 Joules and a frequency of 0.00025 Js? Is it in the visible spectrum?Hint: use the speed of light and energy equations combined.
C= wavelength *(energy) / Plank's constant 3.0*10^8= λ*(1,000,000)/ 6.626*10^-34 1.9878*10-25= λ*(1,000,000) λ= 1.9878*10^-31 sig figs- 2.0^-31 this wave would not be placed in the visible spectrum
C=λE/h 3.0 x 10^8 = C= λ x 1,000,000/6.626 x 10^ -34 1.9878 x 10^-25= wavelength x 1,000,000 1.9878 x 10^-31= wavelength the wave wouldn't be placed in the visible spectrum
C= wavelength X (energy) / Plank's constant 3.0 X 10^8 = λ X (1,000,000)/ 6.626*10^-34 1.9878 X 10-25= λ X (1,000,000) λ= 1.9878 X 10^-31 = 2.0^-31 this wave wouldn't be placed in the visible spectrum
C=wavelengthxfrequency frequency=energy/planck's constant C=wavelengthxenergy/planck's constant 3.0x10^8=wx1000000/6.626x10^-34 wavelength=1.9879 x 10^31 not in the visible spectrum
Energy= Plank's constant multiplied by frequency (E=hν) Speed of light= wavelength multiplied by frequency (C=λν) Isolate ν in both equations: E/h=ν C/λ=ν Substitute both equations for ν: E/h=C/λ Substitute quantities for symbols: 1,000,000J/6.626 x 10^-34=3.0x 10^8/λ Cross multiply: 19.878 x 10^-26= 10^6λ Isolate λ: 19.878 x 10^-26/ 10^6 =λ λ= 19.878 x 10^-32m λ= 2.0 x 10^-31m Convert to nm: 2.0x 10^-31 x 10^9= 2.0 x 10^22 nm
λ= 2.0 x 10^22 nm
This wave will not be placed in the visible spectrum
C=wavelength x E/H 3x10(8th Power) = Wavelength x 1,000,000/6.626 x 10(34th power) 1.9878x10(25th power) = wavelength x 1,000,000 1.9878 x 10(31st power) = wavelength This is not a wave that would be classified in the visible spectrum.
c = wavelength x energy / plank's constant 3.0E8 = wavelength x 1,000,000/6.626E-34 1.9878E-25 = wavelength x 1,000,000 1.9878E-31 = wavelength it wouldn't be in the visible spectrum.
Speed of light(c) = wavelength(l) x frequency(v) 3.0x10^8 m/s = (l) x 2.5x10^-4 Hz 1.2x10^12 = (l) Wavelength = 1.2 x 10^12 nm This wave has a longer wavelength than any waves located in the visible light spectrum. It is probably a radio wave.
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ReplyDeletespeed of light = wavelength x e divided by plank's constant.
ReplyDelete3 x 10^8 = wavelength x 1,000,000 divided by 6.626 x 10^-34.
1.9878 x 10^-25 = wavelength x 1,000,000
1.9878 x 10^-31 = wavelength
C=λE/h
ReplyDelete3.0 x 10^8 = C= λ x 1,000,000/6.626 x 10^ -34
1.9878 x 10^ -25 = λ x 1,000,000
1.9878 x 10^ -31 = λ
C = λE ÷ h
ReplyDelete3.0×10^8 = (λ × 1.0×1000000) ÷ 6.626×10^-34
1.9878×10^-25 = λ × 1000000
λ = 1.9878 x 10^ -31
also I would not expect it to be in the visible spectrum
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteC= wavelength *(energy) / Plank's constant
ReplyDelete3.0*10^8= λ*(1,000,000)/ 6.626*10^-34
1.9878*10-25= λ*(1,000,000)
λ= 1.9878*10^-31
sig figs- 2.0^-31
this wave would not be placed in the visible spectrum
Formula is
ReplyDeleteC= λxE divided by h(Planks constant)
3x10^8= (λx1000000)/ 6.626x10^-34
1.9878x10^-25= 1000000λ
1.988x10^-31=λ
C=λE/h
ReplyDelete3.0 x 10^8 = C= λ x 1,000,000/6.626 x 10^ -34
1.9878 x 10^-25= wavelength x 1,000,000
1.9878 x 10^-31= wavelength
the wave wouldn't be placed in the visible spectrum
C= wavelength X (energy) / Plank's constant
ReplyDelete3.0 X 10^8 = λ X (1,000,000)/ 6.626*10^-34
1.9878 X 10-25= λ X (1,000,000)
λ= 1.9878 X 10^-31
= 2.0^-31
this wave wouldn't be placed in the visible spectrum
C=wavelengthxfrequency
ReplyDeletefrequency=energy/planck's constant
C=wavelengthxenergy/planck's constant
3.0x10^8=wx1000000/6.626x10^-34
wavelength=1.9879 x 10^31
not in the visible spectrum
Formula: C = λE ÷ h
ReplyDelete3.0×10^8 = (λ × 1.0×1,000,000) ÷ 6.626×10^-34
1.9878×10^-25 = λ × 1,000,000
λ = 1.9878 x 10^ -31
Not in the visible spectrum.
-Anna Petrossian
speed of light = wavelengthE/plank's constant.
ReplyDelete3 x 10^8 = wavelength x 1,000,000/ 6.626 x 10^-34.
1.9878 x 10^-25 = wavelength x 1,000,000
1.9878 x 10^-31 = wavelength
no its not in visible spectrum
p.s. how do u do the wavelength sighn
3 * 10^8 = wavelength * 1,000,000/ 6.626 * 10^-34
ReplyDelete1.9878 * 10^-25 = wavelength * 1,000,000
=1.9878*10^-31
No it wouldn't.
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ReplyDeleteEnergy= Plank's constant multiplied by frequency (E=hν)
ReplyDeleteSpeed of light= wavelength multiplied by frequency (C=λν)
Isolate ν in both equations: E/h=ν C/λ=ν
Substitute both equations for ν: E/h=C/λ
Substitute quantities for symbols: 1,000,000J/6.626 x 10^-34=3.0x 10^8/λ
Cross multiply: 19.878 x 10^-26= 10^6λ
Isolate λ: 19.878 x 10^-26/ 10^6 =λ
λ= 19.878 x 10^-32m
λ= 2.0 x 10^-31m
Convert to nm: 2.0x 10^-31 x 10^9= 2.0 x 10^22 nm
λ= 2.0 x 10^22 nm
This wave will not be placed in the visible spectrum
C = wavelength x e/h
ReplyDelete3 x 10^8 = wavelength x 1,000,000 / 6.626 x 10^-34.
1.9878 x 10^-25 = wavelength x 1,000,000
1.9878 x 10^-31 = wavelength
Not in visible spectrum
Formula: C = λE ÷ h
ReplyDelete3.0×10^8 = (λ × 1.0×1,000,000) ÷ 6.626×10^-34
1.9878×10^-25 = λ × 1,000,000
λ = 1.9878 x 10^ -31
sig figs is 2.0 x 10^-31
Not in the visible spectrum.
C=wavelength x E/H
ReplyDelete3x10(8th Power) = Wavelength x 1,000,000/6.626 x 10(34th power)
1.9878x10(25th power) = wavelength x 1,000,000
1.9878 x 10(31st power) = wavelength
This is not a wave that would be classified in the visible spectrum.
thats zorig^^^^^
ReplyDeletec = wavelength x energy / plank's constant
ReplyDelete3.0E8 = wavelength x 1,000,000/6.626E-34
1.9878E-25 = wavelength x 1,000,000
1.9878E-31 = wavelength
it wouldn't be in the visible spectrum.
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ReplyDeleteSpeed of light(c) = wavelength(l) x frequency(v)
ReplyDelete3.0x10^8 m/s = (l) x 2.5x10^-4 Hz
1.2x10^12 = (l)
Wavelength = 1.2 x 10^12 nm
This wave has a longer wavelength than any waves located in the visible light spectrum. It is probably a radio wave.
C = wavelength x e/h
ReplyDelete3 x 10^8 = wavelength x 1,000,000 / 6.626 x 10^-34.
1.9878 x 10^-25 = wavelength x 1,000,000
1.9878 x 10^-31 = wavelength
Not in visible spectrum
-chris berberian