Tuesday, November 29, 2011

Blog 12 due 12/04 at 10:00 pm

Ammonia reacts with oxygen gas to produce nitrogen monoxide and water.
a. Write a blalnced equation for this reaction.
b. If 25 grams of ammonia is placed in a chamber with excess oxygen, how much nitrogen monoxide will be produced?
Posted by at

42 comments:

  1. Lynna OhanianDecember 3, 2011 at 9:08 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO

    ReplyDelete
  2. ArteenDecember 3, 2011 at 11:39 PM

    This comment has been removed by the author.

    ReplyDelete
  3. ArteenDecember 3, 2011 at 11:41 PM

    a) Chemical Equation:
    4NH3+5O2 > 4NO+6H2O

    b) 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g NO

    44.38g NO produced

    ReplyDelete
  4. AnonymousDecember 4, 2011 at 12:33 PM

    A. 4NH3+5O2=4NO+6H2O
    B. 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH31.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g NO
    -Anna Petrossian

    ReplyDelete
  5. AnonymousDecember 4, 2011 at 12:56 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO produced

    ReplyDelete
  6. sevana nourianDecember 4, 2011 at 12:57 PM

    4NH3 + 5O2 = 4NO + 6H2O
    25g NH3/17.031g NH3x1mol NH3 =1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3 = 1.479mol NO
    1.479mol NOx30.00614g
    NO = 44.036g NO

    ReplyDelete
  7. AlecBroutianDecember 4, 2011 at 1:13 PM

    A. 4NH3+5O2=4NO+6H2O
    B. 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH31.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =
    44.38g NO

    ReplyDelete
  8. lara kDecember 4, 2011 at 2:54 PM

    a) Balanced:
    4NH3+5O2 ---> 4NO+6H2O

    b)25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g NO produced

    ReplyDelete
  9. Farah KandahDecember 4, 2011 at 3:45 PM

    4NH3 +5O2 -> 4NO + 6H2O
    25G NH3/17.03G NH3 x 1Mol NH3 = 1.48Mol NH3
    1.48Mol NH3/4Mol NH3 x 4Mol NO = 1.48Mol
    1.48Mol NO/1Mol NO x 30.01G NO = 44.38G NO

    ReplyDelete
  10. Natalie.KDecember 4, 2011 at 4:01 PM

    A: 4NH3 + 5O2 = 4NO + 6H2O
    B: 25g NH3/17.031g NH3x1mol NH3 =1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3 = 1.479mol NO
    1.479mol NOx30.00614g
    NO = 44.036g NO

    ReplyDelete
  11. Andy DanayanDecember 4, 2011 at 4:10 PM

    4NH3 +5O2 -> 4NO + 6H2O

    25G NH3 / 17.03G NH3 x 1Mol NH3 = 1.48Mol NH3
    1.48Mol NH3 / 4Mol NH3 x 4Mol NO = 1.48Mol NO
    1.48Mol NO / 1Mol NO x 30.01G NO = 44.38G NO

    ReplyDelete
  12. Garo KDecember 4, 2011 at 4:23 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4mol NO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO

    ReplyDelete
  13. AregDecember 4, 2011 at 4:39 PM

    a) 4NH3+5O2 > 4NO+6H2O

    b) 25g of NH3 / 17.03g of NH3 x 1mol of NH3 =1.48mol NH3

    1.48mol NH3 / 4mol NH3 x 4molNO =1.48mol NO

    1.48mol NO /1mol NO x 30.01g NO = 44.38g NO

    44.38g or about 44.4g of NO produced

    ReplyDelete
  14. AnonymousDecember 4, 2011 at 4:42 PM

    4NH3+5O2->4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO

    ReplyDelete
  15. karinekhodanianDecember 4, 2011 at 5:20 PM

    a) 4NH3 + 5O2 = 4NO + 6H2O
    b) 25g NH3/17.03g NH3 x1mol NH3 = 1.48mol NH3
    1.48mol NH3/4mol NH3 x4mol NO = 1.48mol
    1.48mol NO/1mol NO x30.01g NO = 44.38g NO

    ReplyDelete
  16. AnonymousDecember 4, 2011 at 5:44 PM

    balanced equation- 4NH3+5O2=4NO+6H2O

    b)- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g NO

    44.38g of NO is produced

    ReplyDelete
  17. Ani KechichianDecember 4, 2011 at 6:17 PM

    A. 4NH3 + 5O2 -> 4NO + 6H2O

    B. 25g NH3 divided by 17.03g NH3 X 1moleNH3 =1.48mole NH3
    1.48mole NH3 divided by 4mole NH3 X 4moleNO =1.48mole NO
    1.48mole NO divided by 1mole NO X 30.01g NO =44.38g NO

    ReplyDelete
  18. garyDecember 4, 2011 at 6:26 PM

    A)4NH+5O2=4NO+6H2O
    B)25g NH3/17.03g NH3 x 1molNH3= 1.48molNH3
    1.48mol NH3/4mol NH3 x 4molNO = 1.48molNH3
    1.38mol NO/1mol NO x 30.01gNO = 44.38gNO

    ReplyDelete
  19. pauline baktiDecember 4, 2011 at 7:42 PM

    A: 4NH3 + 5O2 = 4NO + 6H2O
    B: 25g NH3/17.031g NH3x1mol NH3 =1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3 = 1.479mol NO
    1.479mol NOx30.00614g
    NO = 44.036g NO

    Pauline B

    ReplyDelete
  20. suroDecember 4, 2011 at 7:46 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO
    LIKE A BOSS!!!!!!!!!!!!!

    ReplyDelete
  21. AmandaSirkedzhyanDecember 4, 2011 at 9:03 PM

    Part A- balanced equation:
    4NH3+5O2 > 4NO+6H2O

    Part b-
    25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g NO

    Produced: 44.38g NO

    ReplyDelete
  22. AnonymousDecember 4, 2011 at 10:08 PM

    A)4NH+5O2=4NO+6H2O

    B)25g NH3/17.03g NH3 x 1molNH3= 1.48molNH3

    1.48mol NH3/4mol NH3 x 4molNO = 1.48molNH3
    1.38mol NO/1mol NO x 30.01gNO = 44.38gNO

    Arthur shushanyan

    ReplyDelete
  23. karapetyan77December 4, 2011 at 11:32 PM

    A)4NH+5O2=4NO+6H2O
    B)25g NH3/17.03g NH3 x 1molNH3= 1.48molNH3
    1.48mol NH3/4mol NH3 x 4molNO = 1.48molNH3
    1.38mol NO/1mol NO x 30.01gNO = 44.38gNO

    ReplyDelete
  24. AnonymousDecember 4, 2011 at 11:42 PM

    A) 4NH3 + 5O2 = 4NO + 6H2O

    B) 25g NH3/17.03g NH3 x1mol NH3 = 1.48mol NH3

    1.48mol NH3/4mol NH3 x4mol NO = 1.48mol of NO

    1.48mol NO/1mol NO x30.01g NO = 44.38g of NO

    Zorig Kejejian

    ReplyDelete
  25. AnonymousDecember 4, 2011 at 11:53 PM

    A) 4NH3 + 5O2 = 4NO + 6H2O

    B) 25g NH3/17.03g NH3 x1mol NH3 = 1.48mol NH3

    1.48mol NH3/4mol NH3 x4mol NO = 1.48mol of NO

    1.48mol NO/1mol NO x30.01g NO = 44.38g of NO

    Eddie hovannisian

    ReplyDelete
  26. GasigKDecember 4, 2011 at 11:57 PM

    Equation- 4NH3+5O2->-4NO+6H2O

    b)- 25g NH3 / 17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 / 4mol NH3 x4molNO =1.48mol NO
    1.48mol NO / 1mol NO x30.01g NO =44.38g NO

    ReplyDelete
  27. AnonymousDecember 5, 2011 at 12:04 AM

    a. 4NH3 + 5O2 -> 4NO + 6H2O

    b. 25g NH3 / 17.03g NH3 x 1mol NH3 = 1.48mol NH3
    1.48mol NH3 / 4mol NH3 x 4mol NO = 1.48mol NO
    1.48mol NO / 1mol NO x 30.01g NO = 44.38g NO

    ReplyDelete
  28. ShawntDecember 5, 2011 at 12:20 AM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g N

    ReplyDelete
  29. UnknownDecember 5, 2011 at 8:06 AM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g N
    -chris Berberian

    ReplyDelete
  30. UnknownDecember 5, 2011 at 11:04 AM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g N
    - chris Nalbantian

    ReplyDelete
  31. karapetyan77December 6, 2011 at 2:56 PM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =4

    -Arax Galamdaryan btw mr. P i love foood <3

    ReplyDelete
  32. UnknownDecember 6, 2011 at 3:10 PM

    A- chemical equation: 4 nh3 + 5 o2 > 4 no + 6 h2o B- 25g nh3 / 17.03g nh3 x 1mol nh3 = 1.48mol nh3. 1.48mol nh3 /4 mol nh3 x4molno = 1.48mol no. 1.48mol no /1mol no x30.01g no=4. Vatche antekelian

    ReplyDelete
  33. Hakop GazazyanDecember 6, 2011 at 3:10 PM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g

    ReplyDelete
  34. DavidEyeDecember 6, 2011 at 3:13 PM

    4 NH3+ 5 O2 > 4 NO+ 6 H2O

    b) 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3

    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO

    1.48mol NO /1mol NO x30.01g NO =44.38g NO


    David Eye

    ReplyDelete
  35. kevin khandikianDecember 6, 2011 at 3:15 PM

    a. 4NH3 + 5O2 -> 4NO + 6H2O

    b. 25g NH3 / 17.03g NH3 x 1mol NH3 = 1.48mol NH3
    1.48mol NH3 / 4mol NH3 x 4mol NO = 1.48mol NO
    1.48mol NO / 1mol NO x 30.01g NO = 44.38g NO

    ReplyDelete
  36. Levon G.December 6, 2011 at 3:15 PM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g N

    ReplyDelete
  37. kevin khandikianDecember 6, 2011 at 3:16 PM

    a- Chemical Equation:
    4 NH3+ 5 O2 > 4 NO+ 6 H2O
    b- 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH3
    1.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =44.38g N
    -Shant Broutian

    ReplyDelete
  38. Raffi MarkarianDecember 6, 2011 at 3:17 PM

    A. 4NH3+5O2=4NO+6H2O
    B. 25g NH3 /17.03g NH3 x1mol NH3 =1.48mol NH31.48mol NH3 /4mol NH3 x4molNO =1.48mol NO
    1.48mol NO /1mol NO x30.01g NO =
    44.38g NO

    Raffi markarian

    ReplyDelete
  39. AnonymousDecember 6, 2011 at 3:21 PM

    4NH3 + 5O2 = 4NO + 6H2O
    25g NH3/17.031g NH3x1mol NH3 =1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3 = 1.479mol NO
    1.479mol NOx30.00614g
    NO = 44.036g NO

    ReplyDelete
  40. ChristinaMarkarDecember 6, 2011 at 8:08 PM

    This comment has been removed by the author.

    ReplyDelete
  41. ChristinaMarkarDecember 6, 2011 at 8:09 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO
    -Christina Markarian

    ReplyDelete
  42. AnonymousDecember 7, 2011 at 7:04 PM

    4NH3+5O2=4NO+6H2O
    25g NH3/17.031g NH3x1mol NH3=1.479mol NH3
    1.479mol NH3x4molNO/4mol NH3= 1.479mol NO
    1.479mol NOx30.00614g NO=
    44.036g NO

    Hratch Sarkissian

    ReplyDelete

Subscribe to: Post Comments (Atom)